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Question

Suppose the angle of incidence is X0. Then angle between Shweta and Garima in terms of X0 can be represented as:


A

(X+4)0

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B

(2X-4)0

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C

(2X+4)0

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D

(X-4)0

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Solution

The correct option is B

(2X-4)0


We know the angle of incidence is equal to the angle of reflection. So angle between Garima and normal is (X4)

Since the angle of incidence is X0. Hence the total angle will be X0 + X0 - 40.


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