Suppose the charge of a proton and an electron differ slightly. One of them is −e, the other is (e+Δe). If the resultant of electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much greater than atomic size) apart is zero, then Δe is of the order of [Given mass of hydrogen mh=1.67×10−27 kg]
[NEET- 2017]
Given,
mh=1.67×10−27 kg
And the distance between two hydrogen atoms is d.
Net charge on hydrogen atom q=(e+Δe)−e=Δe
Equating gravitational force and the electrostatic force (because the resultant of them is zero ), we get
Gm2hd2=k(Δe)2d2
(6.67×10−11)(1.67×10−27)2d2=(9×109)(Δe)2d2
⟹ Δe=2.06×10−37 C