The correct options are
C charge may be present inside the surface
D electric field may be zero at every point on the surface
Given that flux of electric field is zero across a closed surface.
So, flux is ϕ=E.A
E= electric field across surface
A= area of closed surface
Since A≠0
means, when ϕ=0 implies E=0 ...(i)
Also, from Gauss Theorem, flux through a closed surface ϕ=qε0=∮→E.−→dS
q= charge (total) enclosed in the closed surface
−→dS= area element on the surface
If ϕ=0⇒ net charge within the surface is zero. ...(ii)
But charge may be present in the surface.
So, when ϕ=0, from (i) and (ii) we see that charge may be present or electric field may be zero.