Question

Suppose the initial charge on the capacitor in Exercise 7.7 is 6 mC. What is the total energy stored in the circuit initially? What is the total energy at later time?

Answer 1

Capacitance of the capacitor, C = 30 μF = 30×10⁻⁶ F

Inductance of the inductor, L = 27 mH = 27 × 10⁻³ H

Charge on the capacitor, Q = 6 mC = 6 × 10⁻³ C

Total energy stored in the capacitor can be calculated by the relation,

Total energy at a later time will remain the same because energy is shared between the capacitor and the inductor.