Question

Suppose the reaction is carried out starting with $14g$ of nitrogen and $15g$ of hydrogen and ammonia is produced. Find the amount of ammonia produced.

• A. $17.04g$
• B. $34.08g$
• C. $51.1g$
• D. $85.2g$
• E. $102g$

Answer 1

The correct option is A $17.04g$

$N_2+3H_2\to 2N{H}_3$

14 g of nitrogen $=\frac{14g}{28g/mol}=0.5mol$

15 g hydrogen $=\frac{15}{2}=7.5mol$

Nitrogen is the limiting reactant.

0.5 mole of nitrogen will produce $0.5\times 2=1.0mol$ of ammonia.

Mass of ammonia produced $=1.0\times 17.04g/mol=17.04g$

Hence, option $A$ is correct.