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Introduction to Le Chatelier's Principle

Suppose the r...

Question

Suppose the reaction $P C l_{5} (g)$ $⇌$ $P C l_{3} (g)$ + $C l_{2} (g)$ as equlibirium in closed vessel. What is the effect on equilibirium concentration of the $C l_{2} (g)$ by adding $P C l_{5}$ at constant temperatue

A

Decrease

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B

Increase

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C

Unaffected

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D

Can not be described without the value of

K_{p}

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Solution

The correct option is B Increase
According to  Le-Chatelier's Principle as we add more and more $P C l_{5}$ then the concentration of the $C l_{2} (g)$ is increased.
hence option 'b' is correct.

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Similar questions

Q. Suppose the reaction

P C l_{5} (g)

⇌

P C l_{3} (g)

C l_{2} (g)

as equlibirium in closed vessel. What is the effect on equilibirium concentration of the

C l_{2} (g)

P C l_{5}

at constant temperatue

Q. A quantity of

P C l_{5}

10 d m^{3}

250^{0} C

P C l_{5}

P C l_{3}

C l_{2}

(g)
At equilibrium the vessel contains 0.1 mole of

P C l_{5}

and 0.2 mole of

C l_{2}

. The equilibrium constant of the reaction is ?

Q. A quantity of

P C l_{5}

was heated in 10

d m^{3}

250^{o}

C

P C l_{5}

P C l_{3}

C l_{2}

At equilibrium the vessel contains 0.1 mole of

P C l_{5}

and 0.2 mole of

C l_{2}

The equilibrium constant of the reaction is:

Q. For the following reaction:

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

0.4 m o l

P C l_{5} (g)

0.2 m o l

P C l_{3} (g)

0.6 m o l

C l_{2} (g)

1 L

K_{c} = 0.2

, then the direction in which reaction proceeds is :

The degree of dissociation of PCl₅(α) obeying the equilibrium,

PCl₅(g) ⇌PCl₃(g) + Cl₂(g) , is approximately related to the pressure at equilibrium by:

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Introduction to Le Chatelier's Principle

Standard XI Chemistry

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