Suppose the rod in the previous problem has a mass of 1 kg distributed uniformly over its length.
(a) Find the initial angular acceleration of the rod.
(b) Find the tension in the supports to the blocks of mass 2 kg and 5 kg.
In this problem the rod has a mass 1 kg
(a) τnet=Inet×α
⇒15=(1.75+0.084)α
⇒α=1500(175+8.4)
= 1500183.4
=8.1 rad/s2(g=10)
=8.01 rad/s2(if g =9.8)
(b) T1−m1g=m1a
⇒ T1=m1a+m1g
=2(a+g)=2(αr+g)
=2(8×0.5+9.8)
=2×13.8
=27.6 N on the first body
In the second body
⇒m2g−T2=m2a
⇒T2=m2g−m2a=5(g−a)
=5(9.8−8×0.5)
=5×5.8=29 N