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Question

Suppose the sequence a1,a2,a3..... is an arithmetic progression of distinct numbers such that the a1,a2,a4,a6.....is a geometric progression. The common ration of the geometric progression is:

A
2
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B
4
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C
a1
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D
not determinable
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Solution

The correct option is B 2
a1,a2,a3,a4,.... are in AP
a4=a1+3dd=(a2a1)
a1,a2,a4,a6,.... are in GP
a4=a1r3r=(a2a1)
a1r3=a1+3dr3=[a1+3da1]=[a1+3a23a1a1]=(3a22a1a1)r3=(3r2)r3r2+r23r+2=0r2(r1)+r2r2r+2=0r2(r1)+(r1)(r2)=0(r1)(r2r+2)=0(r1)(r2+2rr2)=0(r1)(r1)(r+2)=0r1,r=2

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