Question

Suppose the side of a triangle is $6cm$ and the altitude from the opposite vertex to this side is $4.3cm$. Find the area of the triangle.

Answer 1

We have $b=6cm$ and $h=4.3cm$. Hence,
area $=\frac{1}{2}b\times h=\frac{1}{2}\times 6\times 4.3=12.9{cm}^2$.