Suppose the three non-linked autosomal genes A, B and C control coat color in an animal and the dominants alleles A, B and C are responsible for dark colour and the recessive alleles a, b and c are responsible for light color. If a cross between a male of AABBCC genotype and a female of aabbcc genotype produce $640$ offsprings in the F $2$ generation, how many of them are likely to be of the parental genotype?

10

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20

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160

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640

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Solution

The correct option is C $20$
If a cross is made between a male of AABBCC genotype and a female of aabbcc genotype, F $_{1}$ generation will show genotype AaBbCc. In the given example it is given that when F $_{1}$ generation was crossed, 640 offsprings were produced in the F $_{2}$ generation. From the given image, we can say that out of 64 offsprings, only 2 offsprings are having genotype AABBCC and aabbcc. Hence, out of 640 offsprings, there will be 10 offsprings with genotype AABBCC and 10 offsprings with genotype aabbcc. Hence, there will be total 20 offsprings that are likely to be of the parental genotype.
Thus, the correct answer is option B.

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