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Standard VII

Physics

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Question

Suppose we employ a system in which the unit of mass equals $100$ kg, the unit of length equals $1$ km and the unit of time $100$ s and call the unit of energy eluoj (joule written in reverse order), then what is the relation between eluoj and joule?

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Solution

Joule $= K g m^{2} s^{- 2}$

eluoj $= 100$ kg $\times$ $10^{6} m^{2} . {(100)}^{- 2} S^{- 2} = 10^{4}$ Joule.

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Suppose we employ a system in which the unit of mass equals 100 kg, the unit of length equals 1 km and the unit of time 100s and call the unit of energy eluoj (joule written in reverse order), then what is the relation between eluoj and joule?

Joule =Kgm2s−2eluoj =100 kg × 106m2.(100)−2S−2=104 Joule.

Suppose we employ a system in which the unit of mass equals $100$ kg, the unit of length equals $1$ km and the unit of time $100$ s and call the unit of energy eluoj (joule written in reverse order), then what is the relation between eluoj and joule?

Joule $= K g m^{2} s^{- 2}$

eluoj $= 100$ kg $\times$ $10^{6} m^{2} . {(100)}^{- 2} S^{- 2} = 10^{4}$ Joule.