Suppose, we think of fission of a 5626Fe nucleus into two equalfragments, 2813 Al . Is the fission energetically possible? Argue byworking out Q of the process. Given m ( 5626Fe ) = 55.93494 u andm ( 2813 Al ) = 27.98191 u.
Given: The mass of F 26 56 e is 55.93494 u and the mass of A 13 28 l is 27.98191 u .
The fission of F 26 56 e is given by,
F 26 56 e → 2 A 13 28 l
The Q-value of this reaction is given as,
Q-value = ( m i − m f ) c 2 = [ m ( F 26 56 e ) − 2 × m ( A 13 28 l ) ] c 2
Where, the sum of initial mass is m i and the sum of final mass is m f .
By substituting the given values in the above equation, we get
Q-value = [ 55.93494 − 2 × 27.98191 ] c 2 u = [ 55.93494 − 55.96382 ] c 2 u = − 0.02888 c 2 u
We know that,
1 u = 931.5 MeV/ c 2
Therefore, the Q -value is,
Q-value = − 0.02888 c 2 × 931.5 MeV/ c 2 = − 26.902 MeV
The Q-value for the fission reaction is negative. For an energetically possible fission reaction, the Q-value must be positive.
Thus, the fission is not possible.
Given: The mass of
The fission of
The
Where, the sum of initial mass is
By substituting the given values in the above equation, we get
We know that,
Therefore, the
The
Thus, the fission is not possible.
