Suppose x1 & x2 are the point of maximum and the point of minimum respectively of the function f(x)=22x3−9ax2+12a2x+1 respectively, then for the equality x21=x2 to be true the value of ′a′ must be
A
0
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B
a=3+√5(3−√5)
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C
a=3+√5(3−√5)2
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D
None of these
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Solution
The correct option is D None of these f(x)=22x3−9ax2+12a2x+1f′(x)=66x2−18ax+24a2 Discernment for this is D=(18a)2−4(24a2)(66)=324a2−6336a2=−6012a2<0 So, roots are complex, this implies that f′(x) is always positive and f(x) is monotonically increasing and no maxima and minima exits.