Suppose you drop a dice at random on the rectangular region shown in the figure. What is the probability that it will land inside the circle with diameter $1$ m?

\frac{π}{24}

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\frac{π}{28}

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\frac{π}{18}

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\frac{π}{15}

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Solution

The correct option is B $\frac{π}{24}$
Area of the rectangular region $= (3 \times 2)$ sq. m $= 6$ sq. m
Area of the circle $= π {(\frac{1}{2})}^{2}$ sq m $= \frac{π}{4}$ sq. m
Therefore, required probability $= \frac{π / 4}{6} = \frac{π}{24}$

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Suppose you drop a dice at random on the rectangular region shown in the figure. What is the probability that it will land inside the circle with diameter 1 m?

The correct option is B π24Area of the rectangular region =(3×2) sq. m =6 sq. mArea of the circle =π(12)2 sq m =π4 sq. mTherefore, required probability =π/46=π24

Suppose you drop a dice at random on the rectangular region shown in the figure. What is the probability that it will land inside the circle with diameter $1$ m?

The correct option is B $\frac{π}{24}$
Area of the rectangular region $= (3 \times 2)$ sq. m $= 6$ sq. m
Area of the circle $= π {(\frac{1}{2})}^{2}$ sq m $= \frac{π}{4}$ sq. m
Therefore, required probability $= \frac{π / 4}{6} = \frac{π}{24}$