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Question
Supposes S1 and S2 are two unequal circle ; AB and CD are the direct common tangents to these circles. A transverse common tangent PQ cuts AB in R and CD in S. If AB = 10,then RS is.
Supposes S1 and S2 are two unequal circle ; AB and CD are the direct common tangents to these circles. A transverse common tangent PQ cuts AB in R and CD in S. If AB = 10,then RS is.
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Solution
The correct option is C 10
∴RP=RA=10−α
Also SQ=SD=10−β
(1) and (2) ⇒α=β,Hence RS=10
∴RP=RA=10−α
Also SQ=SD=10−β
(1) and (2) ⇒α=β,Hence RS=10
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