Supposing the distance between the atoms of a diatomic gas remains constant, its specific heat per mole (gram mole) at constant volume is

\frac{5}{2} R

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\frac{3}{2} R

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\frac{7}{2} R

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Solution

The correct option is A $\frac{5}{2} R$
$T h e d i s t a n c e b e t w e e n t h e a t o m d o e s n o t c h a n g e t h a t t h e r e a r e 5 d e g r e e s o f f r e e d o m i n t h e d i a t o m i c g a s . ∴ t h e C_{V} w i l l b e s a m e a s \frac{5 R}{2}$

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C_{v} = \frac{5}{2} R

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Molar specific heat at constant volume $C_{v}$ for a monoatomic gas is

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