Question

Supposing the I.P. of hydrogen atom is $960$ eV. Find out the value of principal quantum number having the energy equal to $-60$ eV.

• A. $n=2$
• B. $n=3$
• C. $n=4$
• D. $n=5$

Answer 1

The correct option is C $n=4$

Let us consider, $E=\left(\frac{z^2}{n^2}\right)\times E_H$

Implies that

$n^2=1^2\times \frac{960}{60}$

$n^2=16$

Hence, the correct answer is $n=4$.