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Question

Surface tension of a liquid is 5 N/m. If its thin film is made in a ring of area 0.02m2, then its surface energy will be :

A
5×103 Joule
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B
2.5×103 Joule
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C
1×101 Joule
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D
5×101 Joule
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Solution

The correct option is D 5×101 Joule
The surface energy in any fluid is given as the product of the surface tension of the fluid times the area on which this surface tension is acting.

Since, this is a ring with area 0.02m2 and there are 2 surfaces to it, therefore, the total area = 0.04m2

Hence, the total surface energy would be,

U=TA

U=5×0.04=0.2J

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