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Question

Surface tension of mercury is 0.465 Nm1. The excess pressure inside a mercury drop of diameter 6 mm is then

A
310 Pa
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B
410 Pa
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C
510 Pa
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D
610 Pa
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Solution

The correct option is C 310 Pa
Here, D=6mm
r=D2=6mm2=3mm=3×103
Excess pressure inside the mercury drop is
P=2Sr=2×0.465Nm13×103m=310Pa

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