Sweety runs around a square park of side $75 m$ . Bulbul runs around a rectangular par with length $60 m$ and breadth $45 m$ . Who covers less distance?

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Solution

Distance covered by Perimeter of Sweety = Square Park
$= 4 * s i d e$
$= 4 * 75 m$
$= 300 m$
Distance covered by Bulbul = Perimeter of Rectangular
$= 2 (l + b)$
$= 2 (60 + 45)$
$= 2 (105)$
$= 210 m$
$∴$ Distance covered by Bulbul is less than Sweety.

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Sweety runs around a square park of side 75 m. Bulbul runs around a rectangular par with length 60 m and breadth 45 m. Who covers less distance?

Distance covered by Perimeter of Sweety = Square Park =4∗side =4∗75m =300mDistance covered by Bulbul = Perimeter of Rectangular =2(l+b) =2(60+45) =2(105) =210m∴ Distance covered by Bulbul is less than Sweety.

Sweety runs around a square park of side $75 m$ . Bulbul runs around a rectangular par with length $60 m$ and breadth $45 m$ . Who covers less distance?

Distance covered by Perimeter of Sweety = Square Park
$= 4 * s i d e$
$= 4 * 75 m$
$= 300 m$
Distance covered by Bulbul = Perimeter of Rectangular
$= 2 (l + b)$
$= 2 (60 + 45)$
$= 2 (105)$
$= 210 m$
$∴$ Distance covered by Bulbul is less than Sweety.