Question

System shown in figure is in equilibrium. Find the magnitude of net change in the string tension between two masses just after, when one of the springs is cut. Mass of both the blocks is same and equal to m and spring constant of both springs is k. Report n, if answer is mg/n

Answer 1

$2kx=2mg,\therefore x=\frac{mg}{k}$
After breaking of one spring,
mg - T = ma and T + mg - kx = ma
mg - ma + mg - mg = ma
mg = 2ma
$\therefore a=\frac{g}{2}$
$\therefore a=\frac{g}{2}$
$\Rightarrow \Delta T=\frac{mg}{2}$ (net change in the string tension.)