$t_{1 / 2}$ for a first order reaction is $6.93 s$ , the value of rate constant for the reaction would be ${10 s}^{- 1}$ .

True

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False

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Solution

The correct option is B False
The given statement is false.
The half life period $t_{1 / 2}$ for a first order reaction is 6.93 s, the value of rate constant for the reaction would be $0.1 s^{- 1}$
$k = \frac{0.693}{t_{1 / 2}}$
$k = \frac{0.693}{6.93 s}$
$k = 0.1 s^{- 1}$

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t1/2 for a first order reaction is 6.93 s, the value of rate constant for the reaction would be 10s−1.

The correct option is B False The given statement is false. The half life period t1/2 for a first order reaction is 6.93 s, the value of rate constant for the reaction would be 0.1s−1k=0.693t1/2k=0.6936.93sk=0.1s−1

$t_{1 / 2}$ for a first order reaction is $6.93 s$ , the value of rate constant for the reaction would be ${10 s}^{- 1}$ .

The correct option is B False
The given statement is false.
The half life period $t_{1 / 2}$ for a first order reaction is 6.93 s, the value of rate constant for the reaction would be $0.1 s^{- 1}$
$k = \frac{0.693}{t_{1 / 2}}$
$k = \frac{0.693}{6.93 s}$
$k = 0.1 s^{- 1}$