t = 1 is the solution of the equation 5t - 4 = 1.
True
In order to check whether the above equation 5t - 4 = 1 is satisfied for t =1, we simply put 1 in place of t, as we know that a variable is a number which is not fixed and can any take any given number like 1,2,3..., So the equation upon substituting 't' =1 becomes 5×1 - 4 = 1. Since LHS = 1 and RHS = 1, t =1 satisfies the equation 5t - 4 = 1.