$T_{50}$ (Half-life period) of first - order reaction is 10 minute. Starting with $10 m o l L^{- 1}$ , rate after 20 minute is :

0.0693 m o l L^{- 1} m i n^{- 1}

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0.0693 \times 2.5 m o l L^{- 1} m i n^{- 1}

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0.0693 \times 5 m o l L^{- 1} m i n^{- 1}

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0.0693 \times 10 m o l L^{- 1} m i n^{- 1}

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Solution

The correct option is B $0.0693 \times 2.5 m o l L^{- 1} m i n^{- 1}$
$t_{1 / 2}$ = $\frac{0.693}{k}$

$k = 0.0693 {m i n}^{- 1}$

$r a t e = 0.0693 \times \frac{10}{4}$

$r a t e = 0.0693 \times 2.5 m o l L^{- 1} {m i n}^{- 1}$

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Similar questions

Half life period of a first order reaction is 10 min. Startingwith initial concentration 12M, the rate after 20 min is

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