$t_{7} = 13, S_{14} = 203$ , find the value of $S_{8}$

Open in App

Solution

The term and sum given are for AP
$∴ t_{7} = 13 = a + 6 d$
$S_{14} = \frac{n}{2} [2 a + (n - 1) d]$
$= 7 [2 a + 13 d]$
$∴ d = 3$ and $a = - 5$
$∴$ $S_{8} = \frac{8}{2} (2 a + 7 d) = 4 (- 10 + 21)$
$= 44$

Suggest Corrections

Similar questions

t_{7} = 13

S_{14} = 203

S_{8}

1^{3} + 2^{3} + 3^{3} + . . . . + 20^{3}

T_{1} * T_{2} * T_{7}

T_{7} = 9

t_{1} + t_{7} = 18, t_{4} + t_{10} = 54

520

13, 25, 51, 101, 203, ?

Join BYJU'S Learning Program