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Question

t7=19 and t9=17 find 63rd term.

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Solution

Since series is an AP1
Let a be first term
and d be common difference, so
T7=a+6d=191
and T9=a+8d=172
On solving 1 nd 2, we get
d=163
and a=163
So, T63=a+62d=163+6263=6363=1

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