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New Capacitance in Dielectric

T and P of a ...

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T and P of a gas are 400 K and 41 atms,respectively. The V is 1)400R/41 3)150R/41 2)41R/400 4)300R/4

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T_{c}

P_{c}

400 K

41

atm respectively,

V_{c}

T_{c}

P_{c}

400 K

41

atm respectively,

V_{c}

Q. Solve for r:

41 = 400

[[\frac{100 + r}{100}]^{2} - 1]

△ A B C, \sum \frac{(1 - tan \frac{B}{4}) (1 - tan \frac{C}{4})}{(1 + tan \frac{B}{4}) (1 + tan \frac{C}{4})} =

Δ A B C, \sum \frac{(1 - t a n \frac{B}{4}) (1 - t a n \frac{C}{4})}{1 + t a n \frac{B}{4} (1 + t a n \frac{C}{4})} =

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New Capacitance in Dielectric

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