Question

t and S are zeroes of polynomial x²-6x+a. Find the value of a, if 3t + 2s = 20.

Answer 1

Polynomial P(x) = x² - 6 x + a
Given t and s are the roots. To find a , if 3 t+ 2 s = 20. ---(1)

From the quadratic expression:

We know that
t + s = 6 ---(2)
and t s = a --- (3)

Multiply equation (2) by 2 and subtract from (1) to get:
t = 20 -12 = 8

Substitute this value in(2) to get:
s = 6-8 = -2

Substitute these in (3) to get: a = t s = -16.