T is a point on side QR of - PQR- -S- is a point such that RT - ST- then

The correct option is C PQ + PR > QS In Δ PQR PQ + PR gt; RQ...........(1) RQ = TR + TQ = S T + TQ gt; QS...........(2) [fr ...

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Triangle Inequality

T is a point ...

Question

T is a point on side QR of $Δ$ PQR. "S" is a point such that $R T = S T .$ then

P Q + Q R > Q S

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P Q + P R > Q S

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Q R + P R > Q S

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P Q + P R < Q S

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In Fig. T is a point on side QR of $Δ P Q R$ and S is a point such that RT = ST. Which of the following is true?

In the given figure, T is a point on side QR of $Δ P Q R$ and S is a point such that RT = ST.
Which of the following is true?

In Fig. T is a point on side QR of △PQR and S is a point such that RT = ST. Prove that PQ + PR > QS

Δ

(A) (P R) (Q R) = R S^{2}

(B) Q S^{2} + R S^{2} = Q R^{2}

(C) P R^{2} + Q R^{2} = P Q^{2}

(D) P S^{2} + R S^{2} = P R^{2}

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