T is slower than S. S and T each walk 48 km. The sum of their speeds is 14 kmph and the sum of their time taken is 14 hrs. Then what is S's speed?
8 kmph
10 kmph
12 kmph
16 kmph
Let S's speed = x kmph and T's speed is = (14 - x) kmph
⇒ 48x+4814−x=14
⇒ x = 8 kmph
The ratio between speeds of the S and T is 3:5, and therefore S takes 9 minutes more than the time taken by T to reach the destination. If S had walked at double the speed, in what time would he have covered the distance?
The time taken to travel 30 km upstream and 44 km downstream is 14 hrs. If the distance covered upstream is doubled and the distance covered downstream is increased by 11 km, then the total time taken is 11 hrs more than earlier. Find the speed of the stream and the speed of the boat.