Question

$T-V$ diagram of two mole of a monoatomic gas is as shown in figure
For the process abcda choose the correct options given below

• A. $△U=0$
• B. work done by gas > 0
• C. heat given to the gas is $4R{T}_o$
• D. heat given to the gas is $2R{T}_o$

Answer 1

Answer: (A), (B)

The correct options are
A $△U=0$
B work done by gas > 0

We know that or any cyclic process change in internal energy will be zero,so
$\Delta U=0$
now area under the curve will represent the work done of the process
so it forms a square and area of a square is $(side{)}^2$
$\left(W_{a-b-c-d}\right)$ is always positive.
NOTE: we can also find the work done by converting temperature in form of pressure by applying idea gas equation.