Ta identical loopsnone of copper and other of constanton are removed from a magnetic field within same time interview. In which loop induced current will be greater?

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Solution

Induced emf in the coils would be same.

Then by ohm's Law

V = IR

=> I = V/R

Resistance of the copper wire is less than the resistance of the constantan.

Hence, the induced current will be more in the copper coil than constantan coil.

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Ta identical loopsnone of copper and other of constanton are removed from a magnetic field within same time interview. In which loop induced current will be greater?

Induced emf in the coils would be same. Then by ohm's Law V = IR => I = V/R Resistance of the copper wire is less than the resistance of the constantan. Hence, the induced current will be more in the copper coil than constantan coil.

Induced emf in the coils would be same.

Then by ohm's Law

V = IR

=> I = V/R

Resistance of the copper wire is less than the resistance of the constantan.

Hence, the induced current will be more in the copper coil than constantan coil.