Take a three digit number and reverse it, then subtract the larger number from the smaller number. This number is always divisible by which of the following numbers?

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Solution

The correct option is D 9
The difference of the number and number obtained by reversing the digits (if abc is the number) will be given by:
$(100 \times a + 10 \times b + c) - (100 \times c + 10 \times b + a) = 99 (a - c)$
which is divisible by 9.

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Take a three digit number and reverse it, then subtract the larger number from the smaller number. This number is always divisible by which of the following numbers?

The correct option is D 9The difference of the number and number obtained by reversing the digits (if abc is the number) will be given by: (100×a+10×b+c)−(100×c+10×b+a)=99(a−c) which is divisible by 9.

The correct option is D 9
The difference of the number and number obtained by reversing the digits (if abc is the number) will be given by:
$(100 \times a + 10 \times b + c) - (100 \times c + 10 \times b + a) = 99 (a - c)$
which is divisible by 9.