Take a two digit number 'ab'. Then reverse the digits. If the difference between ab and the new number is always divisible by .

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Solution

The correct option is B 9
Given the 2-digit number is ab

The number ab written in expanded form is 10a + b

If we interchange the digits of ab, the new number is ba.

The number ba written in expanded form is 10b + a

Difference of the number and its reverse is,

Thus, 10a + b - (10b + a) = 9a + 9b = 9 (a + b)

So, it is always divisible by 9.

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