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Question

Take a two digit number 'ab' where a > b. When the difference between this number and the number obtained by reversing its digits is divided by 9, quotient will be equal to


A

a+b

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B

ab

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C

a2b2

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D

a2+b2

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Solution

The correct option is B

ab


Given: 2-digit number ab and a > b.

Expanded form of this 2-digit number ab=10a+b

Number obtained by reversing the digits of ab=ba

Expanded form of the 2-digit number ba=10b+a

Difference between ab and ba is:=(10a+b)(10b+a)=10a+b10ba=9a9b=9(ab)

Now, 9(ab)9=(ab)
Thus, the quotient will be (a - b).


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