Take, bulk modulus of water B=2100MPa. What increase in pressure is required to decrease the volume of 200litres of water by 0.004 percent?
A
210kPa
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B
840kPa
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C
8400kPa
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D
84kPa
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Solution
The correct option is D84kPa Given, bulk modulus of water (B)=2100MPa =2100×106Pa We know that, △P=B(−△VV) Here, △V=0.004 and V=100 =2100×106×(0.004100) =2100×106×41000×100 =8400×106105 =84000Pa =84kPa.