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Question

Take, bulk modulus of water B=2100 MPa.
What increase in pressure is required to decrease the volume of 200 litres of water by 0.004 percent?

A
210 kPa
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B
840 kPa
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C
8400 kPa
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D
84 kPa
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Solution

The correct option is D 84 kPa
Given,
bulk modulus of water (B)=2100 MPa
=2100×106Pa
We know that,
P=B(VV)
Here, V=0.004
and V=100
=2100×106×(0.004100)
=2100×106×41000×100
=8400×106105
=84000 Pa
=84 kPa.

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