wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Take four points P, Q, R, S in a plane. Draw lines by joining different pairs of points. How many lines can you draw in the following cases?
(i) No three of them are collinear
(ii) Three of these points are collinear.

Open in App
Solution

According to the question, we have points P, Q, R and S in a plane.

(i) When no three of them are collinear:

We can draw 6 lines in total. They are as follows:
a by taking P and R
b by taking Q and S
c by taking P and Q
d by taking R and S
e by taking P and S
f by taking Q and R



(ii) When three points are collinear:

Let
P, Q and R be collinear.
Now, we can draw 4 lines in total. They are as follows:

l by taking P and S
m by taking Q and S
n by taking R and S
q by taking P, Q and R


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Euclid's Definitions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon