Taking O as centre, draw an arc 'AC' with radius ‘r’. Cut the arc ‘AC’ at ‘B’, with centre ‘A’ and radius ‘r’. If ‘AB’ is joined in a straight line, what will be the $∠ B A O$ (in degrees)?

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Solution

The length of ‘AB’ is ‘r’(We took 'r' as the radius for drawing an arc to cut arc 'AC'). ‘OA’ and ‘OB’ are radii of the circle. Therefore $△ O A B$ is a equilateral triangle and internal angle $∠ B A O = 60^{\circ}$ .

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Taking O as centre, draw an arc ‘AC’ with radius ‘r’. Cut the arc ‘AC’ at ‘B’, with centre ‘A’ and radius ‘r’. If ‘AB’ is joined in a straight line, what will be the $∠ B A O$ (in degrees)?

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Q. Steps for the construction of a parallelogram ABCD in which AB = 6 cm, BC = 4.5 cm and diagonal AC = 6.8 cm is given below.

Choose the correct order.

1. Draw AB = 6 cm.

2. With A as centre and radius 6.8 cm, draw an arc.

3. With A as centre and radius 4.5 cm, draw an arc.

4. With B as center and radius 4.5 cm draw another arc, cutting the previous arc at C. Join BC and AC.

5. With C as centre and radius 6 cm draw another arc, cutting the previously drawn arc at D. Join DA and DC.

If I do the following constructions step by step, what will be the angles constructed (in degrees)?

Step 1. Draw an arc on the line XY with an arbitrary point O on line XY, as centre and radius r. With the same radius and point of intersection of arc and line, ‘A’, as centre draw another arc on the first arc at point B. So, $∠ A O B$ is __.

Q. In the process of construction of an angle with P as the centre and any radius, draw an arc as shown, which cuts in A. This is the first arc. With A as centre and the same radius, cut this arc in B. This would be the second arc. What will be the value of

∠ B P A

in degrees?

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Taking O as centre, draw an arc 'AC' with radius ‘r’. Cut the arc ‘AC’ at ‘B’, with centre ‘A’ and radius ‘r’. If ‘AB’ is joined in a straight line, what will be the ∠BAO (in degrees)? ___

The length of ‘AB’ is ‘r’(We took 'r' as the radius for drawing an arc to cut arc 'AC'). ‘OA’ and ‘OB’ are radii of the circle. Therefore △OAB is a equilateral triangle and internal angle ∠BAO = 60∘.

Taking O as centre, draw an arc 'AC' with radius ‘r’. Cut the arc ‘AC’ at ‘B’, with centre ‘A’ and radius ‘r’. If ‘AB’ is joined in a straight line, what will be the $∠ B A O$ (in degrees)?

___

The length of ‘AB’ is ‘r’(We took 'r' as the radius for drawing an arc to cut arc 'AC'). ‘OA’ and ‘OB’ are radii of the circle. Therefore $△ O A B$ is a equilateral triangle and internal angle $∠ B A O = 60^{\circ}$ .