Taking O- as origin and the position vectors of A- B are i-3j-2k- 3i-j-2k- The vector OC is bisecting the angle AOB and if C is a point on line AB then C is

The correct option is B 2(i⃗+j⃗ k⃗) Taking magnitude of vectors | OA |=√((0 1)^2+(0 3)^2+(0+2)^2)= √(14) #160;and | OB |=√((0 3)^2+(0 1)^2+(0+ ...

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Section Formula

Taking O' a...

Question

Taking $O$ ' as origin and the position vectors of $A, B$ are $\to i + 3 \to j - 2 \to k, 3 \to i + \to j - 2 \to k$ . The vector $- - \to O C$ is bisecting the angle $A O B$ and if $C$ is a point on line $- - \to A B$ then $C$ is

4 (\to i + \to j - \to k)

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2 (\to i + \to j - \to k)

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(\to i + \to j - \to k)

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6 (\to i + \to j - \to k)

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2 \to i - \to j + 2 \to k

\to i + \to j = \to k

2 \to i + \to j - \to k

\to i + \to j + 2 \to k

\to i + 2 \to j + \to k

\to i + \to j + \to k

\to a = \to i + \to j + \to k, \to a = 2 \to i + \to k, \to c = 2 \to i + \to j + \to k; \to d = \to i + \to j + 2 \to k

(\to a \times \to b) \times (\to c \times \to d) = [\to a \to b \to d] \to c - [\to a \to b \to c] \to d

\to i - \to j + \to k, - \to i + \to j + 2 \to k

¯ ¯¯¯¯¯¯ ¯ A B = 2 \to i - 3 \to j + \to k

¯ ¯¯¯¯¯¯ ¯ C B = \to i + \to j + \to k

¯ ¯¯¯¯¯¯¯ ¯ C D = 4 \to i - 7 \to j

¯ ¯¯¯¯¯¯¯ ¯ A D

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