Question

taking one light year equal to 9.4 *10¹⁵m and one day equal to 86400 s , what will be the speed of light in light year per day if the speed of light in m s^-1 is 3*10⁸ ?

Answer 1

1. 1 light year = $9.4\times {10}^{15}$ m
1 day = 86400 s

2. Speed of light (ms^-1) = $3\times {10}^8\frac{m}{s}$

3. Speed of light (light year day^-1) = $$\begin{gathered} 3\times {10}^8\times \frac{1}{9.4\times {10}^{15}}\times 86400lyda{y}^{-1} \\ =0.27lyda{y}^{-1} \end{gathered}$$