Question

Taking the mass of a proton to be $1.67\times {10}^{-27}$ kg, the order of magnitude of the number of protons in 1 g is $5.88\times {10}^{(20+x)}$. What is $x$.

Answer 1

Mass of proton is $=1.67\times {10}^{-27}kg$ $=1.67\times {10}^{-24}gm$

Number of protons in $1g=$ $\frac{1}{1.67\times {10}^{-24}}$$=\frac{1}{1.67}{10}^{24}$ = $=0.588\times {10}^{24}=5.88\times {10}^{23}$