Taking the unit of work as Joule and the unit of amount of heat as K cal, the magnitude in Joule for mechanical equivalence of heat is:

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.2 \times 10^{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.2 \times 10^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $4.2 \times 10^{3}$
$1 k c a l = 4.2 \times 1000 = 4.2 \times 10^{3} J$

Suggest Corrections

Similar questions

A refrigerator works between 4 C and 30 C. It is required to remove 600 of calories heat every second in order to keep temperature of the refrigerated space constant. The power required is (take 1 cal.=4.2 joule)

Q. Assertion (A) : According to Joule, heat and work are related
Reason (R) : For every 1 cal. of heat we can get 4.186 J of mechanical work.

Q. The unit of Mass is

α

kg. The unit of length is

β

metre and the unit of time is

γ

second. The magnitude of calorie in the new system is:

[1 calorie

=

4.2 Joules]

Q. How much heat energy is required to raise the temperature of unit mass of substance by

1^{\circ} C

Q. A refrigerator works between

4^{0} C

and

30^{0} C

. It is required to remove

600

calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is:
(Take

1 c a l = 4.2 J o u l e s

)

Join BYJU'S Learning Program

Taking the unit of work as Joule and the unit of amount of heat as K cal, the magnitude in Joule for mechanical equivalence of heat is:

The correct option is D 4.2×1031 kcal=4.2×1000=4.2×103 J

The correct option is D $4.2 \times 10^{3}$
$1 k c a l = 4.2 \times 1000 = 4.2 \times 10^{3} J$