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Byju's Answer
Standard XII
Mathematics
Range of Trigonometric Expressions
tan -12+tan -...
Question
tan
−
1
2
+
tan
−
1
3
=
c
o
s
e
c
−
1
x
, then x is equal to -
A
4
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B
√
2
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C
-
√
2
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D
none of these
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Solution
The correct option is
D
none of these
Given,
tan
−
1
2
+
tan
−
1
3
=
c
o
s
e
c
−
1
x
⇒
π
+
tan
−
1
(
−
1
)
=
c
o
s
e
c
−
1
x
⇒
π
−
π
4
=
c
o
s
e
c
−
1
x
⇒
3
π
4
=
c
o
s
e
c
−
1
x
⇒
no solution.
{
−
π
2
≤
c
o
s
e
c
−
1
x
≤
π
2
}
Suggest Corrections
0
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Q.
Assertion :
cosec
−
1
(
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/
2
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+
cos
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1
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−
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cot
−
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1
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−
cot
−
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is equal to
cot
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Reason:
sin
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,
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,
cosec
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sin
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,
cot
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(
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/
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=
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,
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Q.
∫
sin
2
x
cos
4
x
d
x
=
(a)
1
3
tan
2
x
+
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(b)
1
2
tan
2
x
+
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(c)
1
3
tan
3
x
+
C
(d) none of these
Q.
The number of solutions of the equation
tan
-
1
2
x
+
tan
-
1
3
x
=
π
4
is
(a) 2
(b) 3
(c) 1
(d) none of these
Q.
∫
x
4
+
x
4
d
x
is equal to
(a)
1
4
tan
-
1
x
2
+
C
(b)
1
4
tan
-
1
x
2
2
(c)
1
2
tan
-
1
x
2
2
(d) none of these
Q.
Solve the following equations for
x
:
(i) tan
−1
2x + tan
−1
3x = nπ +
3
π
4
(ii) tan
−1
(x + 1) + tan
−1
(x − 1) = tan
−1
8
31
(iii) tan
−1
(
x
−1) + tan
−1
x
tan
−1
(
x
+ 1) = tan
−1
3
x
(iv)
tan
−1
1
-
x
1
+
x
-
1
2
tan
−1
x
= 0, where
x
> 0
(v) cot
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x
− cot
−1
(
x
+ 2) =
π
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,
x
> 0
(vi) tan
−1
(
x
+ 2) + tan
−1
(
x
− 2) = tan
−1
8
79
,
x
> 0
(vii)
tan
-
1
x
2
+
tan
-
1
x
3
=
π
4
,
0
<
x
<
6
(viii)
tan
-
1
x
-
2
x
-
4
+
tan
-
1
x
+
2
x
+
4
=
π
4
(ix)
tan
-
1
2
+
x
+
tan
-
1
2
-
x
=
tan
-
1
2
3
,
where
x
<
-
3
or
,
x
>
3
(x)
tan
-
1
x
-
2
x
-
1
+
tan
-
1
x
+
2
x
+
1
=
π
4
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