Tan -1 a - b -tan -1 a - b - a - b -A- -6B- -4C- -3D- -2

The correct option is B tan^ 1 (a/b ( a b/a+b )/1+a/b ( a b/a+b ) )=tan^ 1 ( a^2 +b^2/a^2 +b^2 )=tan^ 1(1) =π/4 ...

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Improper Integrals

tan -1 a / b ...

Question

$t a n^{- 1} \frac{a}{b} - t a n^{- 1} (\frac{a - b}{a + b})$ =

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