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Question

tan1xytan1xyx+y is equal to (where x>y>0)


  1. /4
  2. π/4
  3. /4
  4. 0


Solution

The correct option is B π/4
tan1xytan1xyx+y
=tan1xytan1[1y/x1+y/x]
=tan1xytan1tan1(1)+tan1yx
=tan1xy+cot1xytan1(tanπ4)
=π2π4
=π4

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