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Question

tan1[3sin2α5+3cos2α]+tan1[tanα4]

=λα4 where π2<α<π2 then λ is 


Solution

tan1[3sin2α5+3cos2α]+tan1[tanα4]

=tan1(3tanα4+tan2 α)+tan1(tan α4)                (3 tan2 α16+4 tan2 α<1)

=tan1(tanα)=α

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