wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

(tan1x)2+(cot1x)2=5π28x=

A
-1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
π58
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C -1
Given ,
(tan1x)2+(cot1x)2=5π28
As we know that ,
tan1x+cot1x=π2
Squaring on both side , we get
(tan1x+cot1x)2=π24
(tan1x)2+(cot1x)2+2tan1xcot1x=π24
5π28+2tan1xcot1x=π24
2tan1xcot1x=3π28
tan1xcot1x=3π216
tan1x[π2tan1x]=3π216
Now, Let
y=tan1x
The Above Equation becomes ,
16y28πy3π2=0
On solving this Quadratic Equation in y , we get
y=π4,y=3π4
Also
y=tan1x
tan1x=π4 tan1x=3π4
So , x=1 x=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Property 4
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon