Question

${\tan }^{-1}x,{\tan }^{-1}y,{\tan }^{-1}z$ are in $A.P$. and x , y , z are also in $A.P$. $(y\ne 0,1,-1)$ then

• A. $x,y,z$ are in $G.P.$
• B. $x,y,z$ are in $H.P.$
• C. $x=y=z$
• D. $(x-y{)}^2+(y-z{)}^2+(z-x{)}^2=0$

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A $x,y,z$ are in $G.P.$
B $x,y,z$ are in $H.P.$
C $x=y=z$
D $(x-y{)}^2+(y-z{)}^2+(z-x{)}^2=0$