Question

$\tan {18}^o+\tan {27}^o+\tan {18}^o.\tan {27}^o=1$

• A. True
• B. False

Answer 1

The correct option is A True

$\tan ({18}^{\circ }+{27}^{\circ })=\tan {45}^{\circ }$

$⟹\frac{\tan {18}^{\circ }+{27}^{\circ }}{1-\tan {18}^{\circ }\tan {27}^{\circ }}=1$

$⟹\tan {18}^{\circ }+\tan {27}^{\circ }=1-\tan {18}^{\circ }\tan {27}^{\circ }$

$⟹\tan {18}^{\circ }+\tan {27}^{\circ }+\tan {18}^{\circ }\tan {27}^{\circ }=1$

So the relation is $\text{True}$