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Question

tan20+2tan50=

A
tan20
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B
cot20
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C
tan50
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D
cot50
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Solution

The correct option is B cot20
tan20°+2tan50°

=tan20°+tan50°+tan50°

tan(A+B)=tanA+tanB1tanAtanB

tanA+tanB=tan(A+B)×(1tanAtanB)

tan20°+tan50°+tan50°

=tan(50°+20°)(1tan20°tan50°)+tan50°

=tan70°(1tan20°cot20°)+tan50°

=tan70°(11)+tan50°

=tan50°=cot20°

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